1131. Maximum of Absolute Value Expression
1131. Maximum of Absolute Value Expression
Given two arrays of integers with equal lengths, return the maximum value of:
|arr1[i] - arr1[j]| + |arr2[i] - arr2[j]| + |i - j|
where the maximum is taken over all 0 <= i, j < arr1.length.
Example 1:
Input: arr1 = [1,2,3,4], arr2 = [-1,4,5,6]
Output: 13
Example 2:
Input: arr1 = [1,-2,-5,0,10], arr2 = [0,-2,-1,-7,-4]
Output: 20
Constraints:
2 <= arr1.length == arr2.length <= 40000
-10^6 <= arr1[i], arr2[i] <= 10^6
- Break the absolute expression
public int maxAbsValExpr(int[] arr1, int[] arr2) {
int[] arr = new int[arr1.length];
int result = 0;
for(int k = 0; k < 4; k++) {
for(int i = 0; i < arr.length; i++) {
switch(k) {
case 0 : arr[i] = arr1[i] + arr2[i] - i; break;
case 1 : arr[i] = arr1[i] - arr2[i] - i; break;
case 2 : arr[i] = -arr1[i] + arr2[i] - i; break;
case 3 : arr[i] = -arr1[i] - arr2[i] - i; break;
}
}
result = Math.max(result, maxDist(arr));
}
return result;
}
public int maxDist(int[] arr) {
int result = 0, max = arr[0];
for(int i = 1; i < arr.length; i++) {
result = Math.max(result, max - arr[i]);
max = Math.max(max, arr[i]);
}
return result;
}