300. Longest Increasing Subsequence
300. Longest Increasing Subsequence
Given an unsorted array of integers, find the length of longest increasing subsequence.
Example:
Input: [10,9,2,5,3,7,101,18]
Output: 4
Explanation: The longest increasing subsequence is [2,3,7,101], therefore the length is 4.
Note:
There may be more than one LIS combination, it is only necessary for you to return the length.
Your algorithm should run in O(n2) complexity.
Follow up: Could you improve it to O(n log n) time complexity?
- Binary Search DP
public int lengthOfLIS(int[] nums) {
if(nums.length == 0) return 0;
int[] dp = new int[nums.length];
dp[0] = nums[0];
int len = 1;
for(int i = 1; i < nums.length; i++) {
// first greater than nums[i]
int l = 0, r = len;
while(l < r) {
int mid = l + (r-l) / 2;
if(dp[mid] >= nums[i])
r = mid;
else
l = mid + 1;
}
if(l == len) {
dp[len++] = nums[i];
} else {
dp[l] = nums[i];
}
}
return len;
}