136. Single Number
Design a Phone Directory which supports the following operations:
get: Provide a number which is not assigned to anyone.
check: Check if a number is available or not.
release: Recycle or release a number.
Example:
// Init a phone directory containing a total of 3 numbers: 0, 1, and 2.
PhoneDirectory directory = new PhoneDirectory(3);
// It can return any available phone number. Here we assume it returns 0.
directory.get();
// Assume it returns 1.
directory.get();
// The number 2 is available, so return true.
directory.check(2);
// It returns 2, the only number that is left.
directory.get();
// The number 2 is no longer available, so return false.
directory.check(2);
// Release number 2 back to the pool.
directory.release(2);
// Number 2 is available again, return true.
directory.check(2);
- HashSet
class PhoneDirectory {
HashSet<Integer> set = new HashSet<>();
/** Initialize your data structure here
@param maxNumbers - The maximum numbers that can be stored in the phone directory. */
public PhoneDirectory(int maxNumbers) {
for(int i = 0; i < maxNumbers; i++) set.add(i);
}
/** Provide a number which is not assigned to anyone.
@return - Return an available number. Return -1 if none is available. */
public int get() {
if(set.isEmpty()) return -1;
int n = set.iterator().next();
set.remove(n);
return n;
}
/** Check if a number is available or not. */
public boolean check(int number) {
return set.contains(number);
}
/** Recycle or release a number. */
public void release(int number) {
set.add(number);
}
}
- A late adding version
class PhoneDirectory {
HashSet<Integer> released = new HashSet<>();
int p;
int max;
/** Initialize your data structure here
@param maxNumbers - The maximum numbers that can be stored in the phone directory. */
public PhoneDirectory(int maxNumbers) {
max = maxNumbers;
}
/** Provide a number which is not assigned to anyone.
@return - Return an available number. Return -1 if none is available. */
public int get() {
if(released.isEmpty() && p == max) return -1;
if(released.isEmpty()) return p++;
int v = released.iterator().next();
released.remove(v);
return v;
}
/** Check if a number is available or not. */
public boolean check(int number) {
return number >= p || released.contains(number);
}
/** Recycle or release a number. */
public void release(int number) {
if(number > p-1) return;
released.add(number);
}
}