74. Search a 2D Matrix
Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
Integers in each row are sorted from left to right.
The first integer of each row is greater than the last integer of the previous row.
Example 1:
Input:
matrix = [
[1, 3, 5, 7],
[10, 11, 16, 20],
[23, 30, 34, 50]
]
target = 3
Output: true
Example 2:
Input:
matrix = [
[1, 3, 5, 7],
[10, 11, 16, 20],
[23, 30, 34, 50]
]
target = 13
Output: false
- Binary Search
public boolean searchMatrix(int[][] matrix, int target) {
if(matrix.length == 0 || matrix[0].length == 0) return false;
int n = matrix.length, m = matrix[0].length;
int l = 0, r = n * m - 1;
while(l <= r) {
int mid = l + (r-l) / 2;
int i = mid / m, j = mid - i * m;
if(matrix[i][j] == target)
return true;
else if(matrix[i][j] < target) {
l = mid + 1;
else
r = mid - 1;
}
return false;
}